MAT 238, Professor Swift

MAT 238, Calculus III

Prof. Swift, Spring 2025

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Schedule

Review of Chapters 16 and 17
Graphs of vector fields with constant divergence and curl. Here is the Mathematica Notebook, VectorFieldDivCurl.nb that made that pdf.

Feynman Lectures on Physics
The two lectures linked to below give an overview of our Chapters 16 and 17. I recommend looking at these if you are interested in physics. (But don't try to understand everything! Just let Feynman's genius wash over you.) Volume II of the Feynman Lectures on Physics is mostly about Electricity and Magnetism.
Differential Calculus of Vector Fields (Volume II, Chapter 2)
Vector Integral Calculus (Volume II, Chapter 3)

Maxwell’s Equations in the special case with no time dependence.
The equations for the electric field \(\mathbf{E}(x,y,z)\) are \(\nabla \cdot \mathbf{E} = \frac{1}{\epsilon_0} \rho, \ \nabla \times \mathbf{E} = \mathbf{0}\), where \(\rho\) is the charge density.
The Divergence Theorem, together with \(\nabla \cdot \mathbf{E} = \frac{1}{\epsilon_0} \rho\) says that
\(\displaystyle \iint_{\mathcal S} {\bf E} \cdot d{\bf S} = \textstyle{\frac 1 {\epsilon_0} } \displaystyle \iiint_{\mathcal W} \rho \, dV = \textstyle \frac{1}{\epsilon_0} Q \), where \(Q\) is the charge inside the closed surface \(\mathcal S\).
The fact that the curl of the (time-idependent) electric field is \(\bf 0\) says that there is an electrostatic potential \(\phi: \mathbb{R}^3 \to \mathbb{R}\) such that \({\bf E} = - \nabla \phi\).

The equations for the magnetic field \(\mathbf{B}(x,y,z)\) are \(\nabla \cdot \mathbf{B} = 0, \ \nabla \times \mathbf{B} = \mu_0 \mathbf{J}\), where \( \mathbf{J}\) is the current density.
The fact that the divergence of the magnetic field is 0 says that there are no magnetic monopoles, and there is a vector potential \({\bf A}: \mathbb{R}^3 \to \mathbb{R}^3\) such that \({\bf B} = \nabla \times {\bf A}\).
Stokes’s Theorem, together with \(\nabla \cdot \mathbf{B} = 0, \ \nabla \times \mathbf{B} = \mu_0 \mathbf{J}\), says that
\( \displaystyle \oint_{\mathcal C} {\bf B}\cdot d{\bf r} = \iint_{\mathcal S} \left (\nabla \times {\bf B} \right ) \cdot d{\bf S} = \mu_0 \iint_{\mathcal S} {\bf J} \cdot d{\bf S} = \mu_0 I \), where \(I\) is the current going throught the closed curve \(\mathcal C\).

The equations get more complicated and interesting when you add time dependence. They describe light, the generation of hydro-electric power, and electric motors.

Section 17.3: Divergence Theorem Paul's notes

Assume that \(\mathcal W\) is a simply connected region in \(\mathbb{R}^3\), and let \(\mathcal{S} = \partial \mathcal W\) be the boundary of \(\mathcal W\), oriented outward. Assume that the vector field \({\bf F}: \mathbb{R}^3 \to \mathbb{R}^3\) is defined and smooth on \(\mathcal W\). The Divergence theorem says
\( \displaystyle \iint_\mathcal{S} {\bf F} \cdot d{\bf S} = \iiint_\mathcal{W} \nabla \cdot {\bf F} \, dV \)

Justification of the Divergence theorem, pictures of the white board: Part 1. We can approximate any shape with minecraft blocks, and then do Part 2
Videos
Divergence Theorem 1
Divergence Theorem 1
Divergence Theorem to Evaluate Flux Integral (Spherical Coordinates)
3D divergence theorem intuition
Flux and the divergence theorem
Divergence Theorem explanation

Section 17.2: Stokes’ Theorem: Paul’s notes
Let \(\mathcal S\) be an oriented, smooth surface in \(\mathbb{R}^3\), and let \(\mathcal C\) be the boundary of \(\mathcal S\) oriented so the right-hand-rule makes the thumb point with the orientation of \(\mathcal S\). Sometimes we write \(\mathcal C = \partial \mathcal S\) which is read “\(\mathcal C\) is the boundary of \(\mathcal S\)”. Let \({\bf F}: \mathbb{R}^3 \to \mathbb{R}^3\) be a smooth vector field. Stokes’ Theorem says that
\( \displaystyle \oint_{\mathcal C} {\bf F}\cdot d{\bf r} = \iint_{\mathcal S} \left (\nabla \times {\bf F} \right ) \cdot d{\bf S}.\)
Justification of Stokes’ Theorem, picture of the white board StokesTheorem.pdf.
Videos
Stokes’ Theorem 1
Stokes’ Theorem 2
Stokes’ theorem intuition
Stokes’ Theorem

Section 17.1: Green’s Theorem: Paul’s notes
Suppose \({\bf F}: \mathbb{R}^2 \to \mathbb{R}^2\) is defined by \({\bf F} (x,y) = \langle P(x,y), Q(x,y)\rangle\), and suppose that \(\mathcal C\) is a positively oriented (CCW), piecewise smooth, simple (no self-intersections), closed curve in \(\mathbb{R}^2\). Let \(\mathcal D\) be the region enclosed by \(\mathcal C\). Then
\(\displaystyle \oint_{\mathcal C} {\bf F}\cdot d{\bf r} = \iint_{\mathcal D} \left (Q_x - P_y \right ) \, dA \)
Justification of Green’s theorem, pictures of the white board: Part 1, Part 2.
Videos
Green's Theorem
Green's Theorem 2
Green's Theorem to find Area Enclosed by Curve (See my example below)
Area using Line Integrals

Example: Find the area of the region enclosed by the curve \(C\) with parameterization \({\bf r}(t) = \langle 5 \cos(t) + \sin(2t), 3 \sin(t) + \cos(2t) \rangle \), \(0 \leq t \leq 2\pi\).
We cannot solve for \(y = f(x)\) at the top or bottom boundaries, so \(A = \int_a^b (y_t(x) -y_b(x) ) \, dx\) is doomed to failure.
Solution: Choose \(\langle P, Q \rangle = \langle 0, x\rangle\) or any other linear vector field that satisfies \(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} = 1\). Then apply Green’s theorem “backwards” to get \[A = \iint_D dA = \oint_C \langle 0,x \rangle \cdot {d \bf r} = \oint_C x \, dy =\int_0^{2\pi} x \frac{dy}{dt} \, dt = \int_0^{2\pi} (\cos(t) + \sin(2t))(3\cos(t) - 2 \sin(2t)) \, dt\] This is not an easy integral, so I'll use technology to evaluate it. Wolfram alpha tells me that \(A = 13\pi \approx 40.8\). This Desmos graph shows that the area is a bit larger than 36, the area of the triangle with vertices (0, -4), (6,2), and (-6,2). This gives some confidence in the answer.

Section 16.4 and 16.5: Surface Integrals
Paul's notes on parametrized surfaces
Paul's notes on Surface Integrals of scalar fields and vector fields

Suppose \(\mathcal S = \{ {\bf r}(u, v) \in \mathbb R^3 \mid a \leq u \leq b, \ c \leq v \leq d \}\) is a parameterized surface. An example is Archimedes' screw, which is related to a helicoid.
The surface integral of \(f: \mathbb{R}^3 \to \mathbb{R}\) is
\( \displaystyle \iint_\mathcal S f \, dS = \int_a^b \int_c^d f({\bf r}(u,v)) \|{\bf r}_u \times {\bf r}_v \| \, dv \, du\).
The surface integral of \({\bf F}: \mathbb{R}^3 \to \mathbb{R}^3\) is
\( \displaystyle \iint_\mathcal S {\bf F}\cdot d{\bf S} = \int_a^b \int_c^d {\bf F}({\bf r}(u,v)) \cdot ({\bf r}_u \times {\bf r}_v) \, dv \, du\).
The value of both of these surface integrals is a scalar (a real number). The vector surface integral is easier to compute and has more applications.

Videos of surface integrals of scalar fields
Parameterized Surfaces
Area of a Parameterized Surface
Surface Integrals
Surface Integrals 2
Surface Integral triangular region
Videos of surface integrals of vector fields
Surface Integral of Vector Field
Surface Integral of Vector Field 2
Surface Integral Using Polar Coordinates

Section 16.3: Conservative Vector Fields
Paul's notes on Fundamental Theorem of Line Integrals and Conservative Vector Fields
With the same \( \mathcal C\) and \(f\) from section 16.2, the fundamental theorem of line integrals is \(\displaystyle \int_{\mathcal C} \nabla f \cdot d{\bf r} = f({\bf r}(b)) - f({\bf r}(a))\).
A gradient vector field is a conservative vector field is a path-independent vector field.
Videos
Fundamental Theorem of Line Integrals
Closed curve line integrals of conservative vector fields
Conservative Vector Fields
Fundamental theorem of line integrals

Section 16.2: Line Integrals
Paul's notes for Scalar and Vector Line Integrals.

Suppose \(\mathcal C = \{ {\bf r}(t) \in \mathbb{R}^3 \mid a \leq t \leq b\}\) is a parameterized curve.
The scalar line integrals of \(f: \mathbb{R}^3 \to \mathbb{R}\) over the curve is \( \displaystyle \int_\mathcal C f \, ds = \int_a^b f({\bf r}(t)) \|{\bf r}'(t) \| \, dt\).
The vector line integral of \({\bf F}: \mathbb{R}^3 \to \mathbb{R}^3\) over the curve is \( \displaystyle \int_\mathcal C {\bf F}\cdot d{\bf r} = \int_a^b {\bf F}({\bf r}(t)) \cdot {\bf r}'(t) \, dt\).
The value of both of these line integrals is a scalar (a real number). The vector line integral is easier to compute and has more applications.

Videos of Scalar Line Integrals (Curve integrals of scalar fields)
Line integral 2D
Line integral 3D
Mass of wire
Videos of Vector Line Integrals (Curve integrals of vector fields)
Parametrization piecewise
Work
Differential form
Line segment

Section 16.1: Vector Fields Paul's notes on Vector Fields and Paul's notes on Curl and Divergence
There are tons of applications for vector fields! Here is a wind map of the USA. Here is the wikipedia page for Maxwell's Equations which describe electric and magnetic fields (E and B). Here is a picture of a vortex behind an airplane wing.
Here is a GeoGebra app to plot a 2D vector field.
Here is my web page on gradient vector fields.
Here is a notebook to plot a 2-dimensional vector field with Mathematica. You can also search the web for programs. Most vector field plotters scale the vectors.
Videos
Two-dimensional vector fields
Divergence and curl (definitely watch this)
Divergence
Sign of the Divergence
Curl
Curl intuition
Curl nuance
Three-dimensional vector fields
Divergence 1
Divergence 2
Curl 1
Curl 2
Curl 3

Section 15.6: Changes of Variables Paul' notes on Change of Variables

Change of variable formula: Let \( (x, y) = G(u, v) \) and assume \(\mathcal D = G([a,b] \times [c,d])\). That is, the region \(\mathcal D\) is the image of the rectangle with \(a \leq u \leq b, \ c \leq v \leq d\). Then
\(\displaystyle \iint_{\mathcal{D}} f(x,y) dx dy = \int_a^b \int_c^d f(G(u,v)) \left | \textstyle \frac{\partial (x,y)}{\partial (u, v)} \right | dv \, du\), where \( \frac{\partial (x,y)}{\partial (u, v)} = \text{det} \begin{bmatrix} \frac{\partial x}{ \partial u} & \frac{\partial x}{ \partial v} \\ \frac{\partial y}{ \partial u} & \frac{\partial y}{ \partial v} \end{bmatrix} \) is the Jacobian of \(G\), also called \(\text{Jac}(G)\).
This formula is a generalization of the substitution rule for definite integrals from Calc I. Here is the one-dimensional version of our new formula:
Let \(x = g(u) \). Then
\( \displaystyle \int_{g(a)}^{g(b)} f(x) \, dx = \int_a^b f(g(u)) g'(u) \, du \).
Note that the \(x\) and \(u\) variables are switched from the usual formula! The focus in Calc III is on a way to handle the region \(\mathcal D\), whereas the focus in Calc I was on finding antiderivatives.

Here is my Mathematica File showing examples of a Change of Variables.
Videos
Change of variables
Triangle
Parallelogram
Jacobian 2x2
Jacobian 2x2
Jacobian 3x3

Section 15.5: Applications
Paul's does not have a stand-alone section on applications.
Videos
Mass 3D
Center of mass of triangle
Center of mass of cube
Center of mass paraboloid

Section 15.4: Double integrals in Polar Coordinates, Triple integrals in Cylindrical or Spherical Coordinates Paul's notes about polar, cylindrical, and spherical coordinates.

\(dA = r \, dr \, d\theta\) Polar coordinates
\(dV = r \, dr \, d\theta \, dz\) Cylindrical Coordinates
\(dV = \rho^2 \sin(\phi) d\rho \, d\phi \, d\theta\) Spherical Coordinates.
Here is a scan of the Spherical Volume Element, from p. 861 of Rogawski and Adams, Calculus, Early Transcendentals (Third edition).
Videos
my video about Integrals in spherical and cylindrical coordinates
Changing to polar
Changing to cylindrical
Volume of sphere
Spherical coordinates

Section 15.3: Triple Integrals Paul's notes

The triple integral of a function \(f: \mathbb{R}^3 \to \mathbb{R}\) over a box \(\mathcal{B} = [a,b]\times[c,d]\times[e,f] = \{(x,y,z) \in \mathbb{R}^3 \mid a \leq x \leq b, c \leq y \leq d, e \leq z \leq f \} \) is
\(\displaystyle \iiint_\mathcal{B} f(x,y,z)\, dV = \int_a^b \int_c^d \int_e^f f(x,y,z) \, dz \,dy \,dx \).

As with double integrals, we hope for the integrand to be a product of three functions of 1 variable. In this case, \(\displaystyle \iiint_\mathcal{B} f(x) g(y) h(z) \, dV = \left ( \int_a^b f(x) \, dx \right ) \left ( \int_c^d g(y) \, dy \right ) \left (\int_e^f h(z) \, dz \right ) \).

The triple integral of a function \(f: \mathbb{R}^3 \to \mathbb{R}\) over the ''Type I of VI'' region \(\mathcal{W} = \{(x,y,z) \in \mathbb{R}^3 \mid a \leq x \leq b, \ h_1(x) \leq y \leq h_2(x), \ g_1(x,y) \leq z \leq g_2(x,y) \} \) is
\(\displaystyle \iiint_\mathcal{W} f(x,y,z)\, dV = \int_a^b \int_{h_1(x)}^{h_2(x)} \int_{g_1(x,y)}^{g_2(x,y)} f(x,y,z) \, dz \,dy \,dx \).
Here is a desmos graph of the region in problem 5, in the case where the sphere has radius 2.
Set 15.3 Extra Credit is worth 2 class points, and asks you to program the Midpoint Sum to approximate a triple integral.

Videos
Triple integral The most recent equation is at time 2:00, but it's not in Paul's notes.
Tetrahedron
Cylinder
Volume
Different order of integration

Section 15.2: Double Integrals over Non-Rectangular Regions Paul's notes

Let \(\mathcal D = \{ (x,y) \in \mathbb{R}^2 \mid a \leq x \leq b, \ g_1(x) \leq y \leq g_2(x) \} \). Then we can integrate \(f\) over the region \(\mathcal D\) as follows:
\(\displaystyle \iint_D f(x,y) \, dA = \int_a^b \left ( \int_{g_1(x)}^{g_2(x)} f(x,y) \, dy \right ) dx\). Note that the thing inside the parentheses is just a function of \(x\). This \(\mathcal D\) is called a type I region in Paul's notes. There is also a type II region, for which the "outside" integral is \(\int_c^d \cdots dy \). Note that many regions are neither type I nor type II.

Videos
Triangular region
More general region
More general region
Both order of integration
Change order of integration
Change order of integration

Section 15.1: Double Integrals over Rectangles Paul's notes and more of Paul's notes

\(\displaystyle \iint_{[a,b]\times[c,d]} f(x,y)\, dA = \int_a^b \left ( \int_c^d f(x,y) \,dy \right ) \,dx = \int_c^d \left (\int_a^b f(x,y) \,dx \right ) \,dy\).
Usually the parentheses are left out. The super-simple special case is ...
\(\displaystyle \iint_{[a,b]\times[c,d]} f(x) g(y)\, dA = \left( \int_a^b f(x) \, dx \right ) \left ( \int_c^d g(y) \,dy \right )\).

Videos
Double integrals
Approximate volume from table of values
Approximate double integral from contour plot
Fubini
Double integral on rectangular region
Average value over rectangular region

Section 14.8: Lagrange Multipliers Paul's notes

Help on Problem 4.
Many of the optimization problems from Calc 1 can be easily done with Lagrange Multipliers. This new method also give insight into the solutions of these optimization problems. See Paul's notes on Optimization. We will look at example 4 in Paul's notes, which is similar to problem 6 on the webwork.
Videos
Lagrange Multipliers two variables one constraint
Lagrange Multipliers three variables one constraint
Global extrema on disk
Lagrange Multipliers three variables two constraints

Section 14.7: Part 2: Local Extrema
Paul's notes on relative extrema which is another word for local extrema.

Here is a Desmos 3D graph of quadratic functions \(f(x,y)\) with a critical point at \((0,0)\).
Here is a Desmos 3D graph of a cubic function \(f(x,y)\) with a critical point at \((0,0)\). The graph is called a "Monkey Saddle", since there room for the monkey's tail as well as their two legs.

Videos
Critical points, second derivative test
Local extrema
Local extrema
Minimum distance of point from plane
Minimum surface area of box
Maximum volume of box
Minimum cost of box
Distance between point and cone

Section 14.7: Part 1: Global Extrema
Paul's notes on absolute extrema which is another word for global extrema.

For today's homework you need these definitions:
Consider the function \(f: D \to \mathbb{R}\) with domain \(D \subseteq \mathbb{R}^2\).

The point \((a,b) \in D\) is a critical point of \(f\) provided \( \nabla f(a,b) = \langle 0,0\rangle\) or \(\nabla f(a,b)\) does not exist.

We say that \(f\) has a global maximum at \((x_1, y_1)\) provided \((x_1, y_1) \in D\) and \(f(x_1, y_1) \geq f(x,y)\) for all \((x,y) \in D\). In this case we say that the global maximum value of \(f\) is \(f(x_1, y_1)\).

Videos
Global extrema, rectangular domain
Global extrema, circular domain

Section 14.6: The Chain Rule. Paul's notes
Figure showing the dependency diagram for Problem 4 on the webwork
Videos
Chain rule with partial derivatives from the Organic Chemistry tutor
The Multi-variable chain rule from Trefor Bazett

Section 14.5: The Gradient and Directional Derivatives. Paul's notes on the directional derivative and the gradient
For \(f: \mathbb R^2 \to \mathbb R\), the gradient of \(f\) is the function \(\nabla f: \mathbb R^2 \to \mathbb R^2\) defined by \(\nabla f(x,y) = \langle f_x(x,y), f_y(x,y)\rangle\). Thus, the gradient of \(f\) evaluated at the point \((a,b) \in \mathbb R^2\) is the vector \(\nabla f(a,b) = \langle f_x(a,b), f_y(a,b)\rangle\).

The directional derivative of \(f: \mathbb R^2 \to \mathbb R\) in the direction of \({\bf v} \in \mathbb R^2\) at the point \((a,b) \in \mathbb R^2\) is defined as \(D_{\bf v}f(a,b) = g'(0)\), where \(g(t) = f((a,b) + t \hat{\bf v}) \), where \(\hat{\bf v} = \frac{\bf v}{\|\bf v\|}\) is the unit vector in the direction of \(\bf v\). The best way to compute the directional derivative is \(D_{\bf v}f(a,b) = \nabla f(a,b) \cdot \hat{\bf v}\).

My web page on gradients.
Videos
My video on problem 6 in the WeBWorK
My video on problem 8 in the WeBWorK
Gradient
Directional Derivative
Directional Derivatives and the Gradient
Max rate of change
Directional Derivative in 3D calc plotter
Gradient in 3D calc plotter
Normal vector
Tangent plane example

Section 14.4: The Tangent Plane to the graph \(z = f(x,y)\)
The local linearization of \(f: \mathbb{R}^2 \to \mathbb{R}\) at \( (x,y) = (a,b) \) is \(L(x,y) = f(a,b) + f_x(a,b)(x-a) + f_y(y-b)\).
An equation of the tangent plane to \(z = f(x,y)\) at \((x,y, z) = (a,b, f(a,b) )\) is \(z = L(x,y)\).
The tangent plane approximation is \(f(x,y) \approx L(x,y) \) for \( (x,y) \approx (a,b) \).

Paul's notes
Videos
Local linearization
Tangent plane
Tangent plane (exponential)
Tangent plane (trigonometric)

14.3: Partial derivatives
Paul's notes have 3 sections: Partial derivatives, their interpretation, and higher order partial derivatives
Here are pictures of a demonstration that mixed partial derivatives are equal: page 1 and page 2.
Videos
Partial derivatives
Partial derivative example
Partial derivative from contour plot
Second partial derivatives
Second partial derivatives

Section 14.2: Limits of Real-Valued Functions of Two Variables Paul's notes
Videos
Limits are...weird..for multi-variable functions
Limits of Functions of Two Variables
Example 1
Example 2
Example 3

Section 14.1: Real-Valued Functions of Several Variables Paul's Notes.
Here is a reminder about the web-based apps for 3D graphing:
Desmos 3D, GeoGebra 3D calculator, and (probably the best choice) CalcPlot3D app. Feel free to let me know about other apps.

Here is a pdf of the level surface of problem 12 in set 14.1. Even though this is a static image, it is much easier to decipher than the figure in webwork. This new pdf also shows the slices with \(x, y\) or \(z = 0\) or \(\pm 2.5\) in blue. For example, you can count 2 slices down from the blue \(z = 0\) slice to see the slice at \(z = -1\). (The distance between slices is \(\Delta x, \Delta y\), or \(\Delta z = 0.5\).)
Hint: Consider the symmetry of the surface. For example, the slices at \(x = -1\) and \(x = 1\) look the same. Also, the four slices at \(z = \pm 1\) and \(y = \pm 1\) all look the same!

That image for problem 12 was made with Mathematica. See this site with a link to Mathematica at NAU. You can get Mathematica for your own computer for free since we have a site license!

Videos
Finding domain
Level curves, contour plot
Function value from contour plot
Increasing or decreasing from contour plot
Traces
Graph Two Variable Function with 3D Calc Plotter
Contour plot with 3D Calc Plotter

Midterm 1 was in class on Monday, February 10.
A sample Midterm 1 with solutions are posted on Canvas.

Section 13.3 and 13.5: Speed, velocity, and acceleration
Paul's notes on Arc Length with Vector Functions
Paul's notes on Velocity and Acceleration
Videos
Velocity, speed, direction, and acceleration
Velocity and Position from Acceleration

Section 13.2: Calculus of vector-valued functions Paul's notes
Videos
Derivative of vector-valued functions
Properties
More properties
Equation of tangent line
Angle of two curves
Integration with Initial Conditions
Definite integral

Section 13.1: Vector-valued functions Paul's notes
Here are 3 different web-based 3D graphing programs:
Desmos 3D, GeoGebra 3D calculator, and CalcPlot3D app. Feel free to let me know about other apps.
Here is a helix made with Desmos 3D.
Here is are two surfaces in \(\mathbb{R}^3\). Find a parameterization of the intersection.
Mathematica is available to you with a site license. Here is a Mathematica notebook, helix.nb, that will plot a parameterized curve in \(\mathbb{R}^3\). It is harder to use than some other programs, but the pictures are beautiful.
This Mathematica notebook will Plot 2 Surfaces And 1 Curve.
Videos
Vector valued functions
Domain of a Vector Valued Function
space curves in 3D Calc Plotter
Curve of intersection of two surfaces
Curve of intersection of two surfaces
Vector Valued Function from a Rectangular Equation

Section 12.7: Cylindrical and Spherical Coordinates.
Here are Paul's notes on polar, cylindrical, and spherical coordinates.
BEWARE! Paul lies to you. He writes the formula “\(\theta = \tan^{-1} (\frac y x )\)”, which is wrong in two ways: (1) That formula is fine in quadrant I but it is false in quadrants II and III, and (2) it uses the abominable notation “\(\tan^{-1}\)” instead of “\(\arctan\)”.
\(f(\theta) = \tan(\theta)\) is not a one-to-one function so its inverse is not defined. Instead, \(\arctan(t)\) is the unique \(\theta\) between \(-\pi/2\) and \(\pi/2\) whose tangent is \(t\).
Instead, write is “\(\tan(\theta) = \frac y x\)” To compute \(\theta\) you need to draw a darn picture!
Here is a figure about how to compute theta in polar or cylindrical or spherical coordinates using the picture you have drawn.
For those who prefer a formula, I wrote this algorithm for finding \(\theta\). Note that \(\frac y x\) is undefined if \(x = 0\), so those cases are handled first. I don't intend you humans to follow this algorithm exactly: Just draw the #!#! picture.
BEWARE! The roles of \(\theta\) and \(\phi\) are switched in physics and math. We are using the math convention, which is superior. In our math notation, the coordinate \(\theta\) is the same in polar, cylindrical and spherical coordinates: \(\tan(\theta) = \frac y x\).
Videos
Cylindrical Coordinates
Spherical Coordinates
Cartesian Coordinates to Spherical
Spherical Coordinates to Cartesian
Cartesian Coordinates to Cylindrical
Cylindrical Coordinates to Cartesian
Cylindrical Equations to Rectangular
Rectangular Equations to Cylindrical
Spherical Equations to Rectangular
Rectangular Equation to a Spherical
Spherical Equation to a Rectangular

Section 12.6: Quadratic Surfaces Paul's notes
Here are some quadratic surfaces plotted in desmos 3d.
Another option is using the "implicit plot" feature of CalcPlot3D CalcPlot3D has more features than desmos 3d, but is consequently harder to use.

Videos
how to plot surfaces in 3D Calc Plotter.
The following videos have more detail than you need. They use the term "quadric surface" which is another name for "quadratic surface". You do not need to learn the names of these surfaces.
Cylindrical Surfaces
Quadric Surfaces
Ellipsoid
Elliptical Cone
Elliptical Paraboloid
Hyperbolic Paraboloid

Section 12.5: Planes in space Paul's notes
Desmos graph for the line in \(\mathbb{R}^2\) through the point (2, 3) with the normal vector (2, -1). An equation is 2(x-2) - (y-3) = 0

Desmos graph for the plane \(\mathbb{R}^3\) through point (-1, 2, 1) with the normal vector (2, -1, 3). An equation is 2(x+1) - (y-2) + 3(z-1) = 0

Videos
Normal equation of plane
Point of Intersection of a Plane and a Line
Point of Intersection of a Plane and a Line
Intersection to two planes
Line through a point and perpendicular to a plane
Plane given with point and parallel plane
Plane given with three points
Plane given with three points
Plane given with point and orthogonal line
Angle between two planes
Distance between point and plane
Distance between parallel planes
Distance between line and point

Section 12.4: The Cross Product. Paul's notes
Example: calculation of the cross product done in two ways. This is my problem 6 on the WeBWorK. You only need to do it one way, but it's comforting that they give the same answer.
Suggested videos on matrices
Multiplying matrices
2x2 determinant
3x3 determinant
Suggested videos on the cross product
Cross product
Cross product
Cross product example
Area of space triangle
Volume of parallelepiped

Section 12.3: The Dot Product. Paul's notes
Suggested videos.
Dot product
Angle between vectors
Parallel and perpendicular components
In-class group work. The methane molecule \(C H_4\) has 4 Hydrogen atoms at the vertices of a tetrahedron, with a single carbon atom at the center. We can place the carbon atom at \( (0,0,0) \), and the 4 Hydrogen atoms at \( (1,1,1)\), \((1, -1,-1)\), \( (-1,1, -1)\), and \(( -1,-1,1) \).
This desmos3D graph shows a Methane molecule. ,
Find the bond angle, which is the angle between any two vectors from the carbon atom to a hydrogen atom. First get an exact angle in terms of the arccos function, then approximate the angle to the nearest degree using technology. Solutions.

Here are some formulas needed for the webwork. Only some are in Paul's Notes.
It is easiest to make sense of these formulas using the notation \(\hat{\bf a}\) (pronounced a-hat) for the unit vector in the direction of \(\bf a\). To compute that unit vector, use the formula \(\hat{\bf a} = \frac{\bf a}{\|\bf{a}\|}\).
The component of \(\bf b\) along \(\bf a\) is \(\hat{\bf a} \cdot {\bf b} = \frac{\bf a \cdot {\bf b}}{\| {\bf a} \|} = \| \bf b \| \cos(\theta)\), which is a scalar.
The projection of \(\bf b\) parallel to \(\bf a\) is \({\bf b}_{\| {\bf a}} = (\hat{\bf a} \cdot {\bf b}) \hat {\bf a} = \frac{({\bf a} \cdot {\bf b}) {\bf a}}{\| {\bf a} \|^2}\), which is a vector. Note that the final expression has no square roots.
The projection of \(\bf b\) perpendicular to \(\bf a\) is \({\bf b}_{\perp {\bf a}} = {\bf b} - {\bf b}_{\| {\bf a}} \), which is a vector.
Note that \({\bf b} = {\bf b}_{\| {\bf a}} + {\bf b}_{\perp {\bf a}} \) must hold (by definition), and it turns out that \({\bf b}_{\| {\bf a}} \cdot {\bf b}_{\perp {\bf a}} = 0\), so these two projections are orthogonal to each other.

Here is a scan of a version of set 12.3, problem 9, with nice numbers. This example should hopefully give some intuition about the parallel and orthogonal projections of vectors.

Section 12.2: Vectors in \(\mathbb{R}^3\) Paul's notes
Suggested videos.
Parametric equation of line in 3D
Parametric equation of line in 3D
Intersection of two lines

Section 12.1: Vectors (Note: The section number 12.1 follows the Rogowski and Adams textbook.)
Paul's notes on basics and vector arithmetic.
Here is my version of webwork problem 5.
The answer to one version of WeBWorK problem 10 in set 12.1 is x = a + 1.6 b. (So type 1 and 1.6 into the two blanks.) This figure shows the vectors. Here is a Mathemetica notebook to allow arbitrary linear combinations of a and b.
Suggested videos.
Vector operations: Sum, scalar multiple, dot product
Length of a 3D vector
Unit vectors: Direction of a vector
Plotting points

WeBWorK set 01: Review of Calculus
Differentiation Shortcuts
Here is the Big Picture of Calculus.


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